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Discussion Starter · #1 ·
If this topic has been discussed before, please point me to the right thread as I can't seem to find anything.



OK...



When the M&P is loaded and ready to fire (I'm ignoring any safeties for this discussion) the striker is held by the raised rear lip of the sear.



As you pull the trigger, the striker block is lifted allowing movement of the striker and the sear is pivoted to release the striker.



Striker launches and ignites the cartridge (yes, I left that simplified)



Now, the slide is kicked back. However, the sear is still flat as the trigger has not been released. How is it that the striker ends up caught on the sear again?



I figure the slide moving forward is what recocks the striker, but I don't see what it catches on. I assume that the 'trigger reset' is the striker and sear being returned to the firing position, but returned from what?



The only thing I can see is that when the sear is flat, it sits slightly higher than the well behind it. I suppose that the striker could catch on this tiny raised area, but if that is the case, DAMN that is asking a lot.



Can someone explain exactly how this part of the action works?



Thanks
 

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Discussion Starter · #3 ·
Bullet time rotation and that fancy camera used on CSI that allows you to travel inside places that no human has ever traveled before. (^_^)



Actually, a lot of this comes from taking the pistol apart and SLOWLY doing my own trigger job. I've assembled and disassembled so many times, I think I am starting to dream about it. (^_^)
 

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Look on the underside of the slide, and you will note two channels on either side of the striker box. One of them has a bump in it. Now look at the sear/triggerbar interface. Push the trigger bar towards the frame and you will the the trigger bar slip of the sear and the sear drop back down. The as the slide moves back that bump in the channel pushes trigger bar sideways towards the frame and lets the sear reset. Or at least I think thats what happens.
 
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